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Popular >

integral from-1 to 1 of (y-1)

Solution

\int_{- 1}^{1} (y - 1) d y

Solution

- 2

Solution steps

\int_{- 1}^{1} y - 1 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} y d y - \int_{- 1}^{1} 1 d y

\int_{- 1}^{1} y d y = 0

\int_{- 1}^{1} 1 d y = 2

= 0 - 2

Simplify

= - 2

Popular Examples

integral from-5 to 5 of g(x)

\int_{- 5}^{5} g (x) d x

integral from 0 to 1 of r^2sqrt(1-r^2)

\int_{0}^{1} r^{2} 1 - r^{2} d r

integral from pi/3 to pi/2 of sin^3(x)

\int_{\frac{π}{3}}^{\frac{π}{2}} sin^{3} (x) d x

integral from 2 to 6 of (4x^3-x+2)

\int_{2}^{6} (4 x^{3} - x + 2) d x

integral from 1 to 4 of (u-9)/(sqrt(u))

\int_{1}^{4} \frac{u - 9}{u} d u

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (y-1) ?
The integral from-1 to 1 of (y-1) is -2