What is (\partial)/(\partial x)(cos(4x)) ?

The answer to (\partial)/(\partial x)(cos(4x)) is -sin(4x)*4

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(\partial)/(\partial x)(cos(4x))

\frac{\partial}{\partial x} (cos (4 x))

- sin (4 x) \cdot 4

Solution steps

\frac{\partial}{\partial x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{\partial}{\partial x} (4 x)

= - sin (4 x) \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x) = 4

= - sin (4 x) \cdot 4

\frac{\partial}{\partial y} (e^{x} + z^{2})

f (x) = \frac{1}{x + 4}

\int e^{x} + 2 cos (x) - \frac{3}{cos ^{2} ( x )} d x

\frac{\partial}{\partial y} (\frac{3 y}{x ^{2} + y ^{2}})

x \to 0 lim (\frac{cos ( x )}{x - \frac{π}{2}})

What is (\partial)/(\partial x)(cos(4x)) ?
The answer to (\partial)/(\partial x)(cos(4x)) is -sin(4x)*4