What is the integral from 0 to infinity of 1/(y^3) ?

The integral from 0 to infinity of 1/(y^3) is diverges

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integral from 0 to infinity of 1/(y^3)

\int_{0}^{\infty} \frac{1}{y ^{3}} d y

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{y ^{3}} d y

Compute the indefinite integral:

\int \frac{1}{y ^{3}} d y = - \frac{1}{2 y ^{2}} + C

Compute the boundaries:

\int_{0}^{\infty} \frac{1}{y ^{3}} d y =

diverges

= diverges

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What is the integral from 0 to infinity of 1/(y^3) ?
The integral from 0 to infinity of 1/(y^3) is diverges