What is the integral from-1 to 2 of sqrt(x+2)x^2 ?

The integral from-1 to 2 of sqrt(x+2)x^2 is 562/105

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integral from-1 to 2 of sqrt(x+2)x^2

\int_{- 1}^{2} x + 2 x^{2} d x

\frac{562}{105}

Decimal Notation

5.35238 \dots

Solution steps

\int_{- 1}^{2} x + 2 x^{2} d x

Apply u-substitution

: \int_{1}^{4} (u - 2)^{2} u d u

= \int_{1}^{4} (u - 2)^{2} u d u

Expand

(u - 2)^{2} u : u^{\frac{5}{2}} - 4 u^{\frac{3}{2}} + 4 u

= \int_{1}^{4} u^{\frac{5}{2}} - 4 u^{\frac{3}{2}} + 4 u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} u^{\frac{5}{2}} d u - \int_{1}^{4} 4 u^{\frac{3}{2}} d u + \int_{1}^{4} 4 u d u

\int_{1}^{4} u^{\frac{5}{2}} d u = \frac{254}{7}

\int_{1}^{4} 4 u^{\frac{3}{2}} d u = \frac{248}{5}

\int_{1}^{4} 4 u d u = \frac{56}{3}

= \frac{254}{7} - \frac{248}{5} + \frac{56}{3}

Simplify

\frac{254}{7} - \frac{248}{5} + \frac{56}{3} : \frac{562}{105}

= \frac{562}{105}

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What is the integral from-1 to 2 of sqrt(x+2)x^2 ?
The integral from-1 to 2 of sqrt(x+2)x^2 is 562/105