What is area y=x^2-4,y=-2x ?

The answer to area y=x^2-4,y=-2x is -(16sqrt(5))/3+12sqrt(5)

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area y=x^2-4,y=-2x

area

y = x^{2} - 4, y = - 2 x

- \frac{16 5}{3} + 125

Decimal Notation

14.90711 \dots

Solution steps

Apply the area formula:

\int_{- 1 - 5}^{- 1 + 5} x^{2} - 4 + 2 x d x

Solve

\int_{- 1 - 5}^{- 1 + 5} x^{2} - 4 + 2 x d x : - \frac{16 5}{3} + 125

The area is:

= - \frac{16 5}{3} + 125

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What is area y=x^2-4,y=-2x ?
The answer to area y=x^2-4,y=-2x is -(16sqrt(5))/3+12sqrt(5)