What is the integral from 2 to 0 of sin(x) ?

The integral from 2 to 0 of sin(x) is cos(2)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 0 of sin(x)

\int_{2}^{0} sin (x) d x

cos (2) - 1

Decimal Notation

- 1.41614 \dots

Solution steps

\int_{2}^{0} sin (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{2} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - [- cos (x)]_{0}^{2}

Compute the boundaries:

- cos (2) + 1

= - (- cos (2) + 1)

Simplify

= cos (2) - 1

\int_{4}^{5} \frac{2}{x ^{2} - 1} d x

\int_{- 1}^{0} (x^{2} - 2 x - \frac{1}{3}) d x

\int_{\frac{1}{2}}^{\frac{3}{2}} (x + \frac{1}{x}) d x

\int_{2}^{3} x^{4} ln (x) d x

\int_{1}^{5} 3 x^{4} sin (2 x) d x

What is the integral from 2 to 0 of sin(x) ?
The integral from 2 to 0 of sin(x) is cos(2)-1