What is the integral from 0 to 2 of (x^2)/(16) ?

The integral from 0 to 2 of (x^2)/(16) is 1/6

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integral from 0 to 2 of (x^2)/(16)

\int_{0}^{2} \frac{x ^{2}}{16} d x

\frac{1}{6}

Decimal Notation

0.16666 \dots

Solution steps

\int_{0}^{2} \frac{x ^{2}}{16} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{16} \cdot \int_{0}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{2}

= \frac{1}{16} [\frac{x ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= \frac{1}{16} \cdot \frac{8}{3}

Simplify

= \frac{1}{6}

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What is the integral from 0 to 2 of (x^2)/(16) ?
The integral from 0 to 2 of (x^2)/(16) is 1/6