What is the integral from 2 to 6 of (3/184 x^2-3/92) ?

The integral from 2 to 6 of (3/184 x^2-3/92) is 1

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integral from 2 to 6 of (3/184 x^2-3/92)

\int_{2}^{6} (\frac{3}{184} x^{2} - \frac{3}{92}) d x

1

Solution steps

\int_{2}^{6} \frac{3}{184} x^{2} - \frac{3}{92} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{6} \frac{3}{184} x^{2} d x - \int_{2}^{6} \frac{3}{92} d x

\int_{2}^{6} \frac{3}{184} x^{2} d x = \frac{26}{23}

\int_{2}^{6} \frac{3}{92} d x = \frac{3}{23}

= \frac{26}{23} - \frac{3}{23}

Simplify

\frac{26}{23} - \frac{3}{23} : 1

= 1

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What is the integral from 2 to 6 of (3/184 x^2-3/92) ?
The integral from 2 to 6 of (3/184 x^2-3/92) is 1