What is the integral from 1 to infinity of 3x^{-2} ?

The integral from 1 to infinity of 3x^{-2} is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to infinity of 3x^{-2}

\int_{1}^{\infty} 3 x^{- 2} d x

3

Solution steps

\int_{1}^{\infty} 3 x^{- 2} d x

Compute the indefinite integral:

\int 3 x^{- 2} d x = - \frac{3}{x} + C

Compute the boundaries:

\int_{1}^{\infty} 3 x^{- 2} d x = 0 - (- 3)

= 0 - (- 3)

Simplify

= 3

\int_{0}^{π} 7 x sin (x) d x

\int_{7}^{- 5} g (x) d x

\int_{0}^{8} 2 x e^{- 0.2 x} d x

\int_{1}^{3} 3 x 2 x + 3 d x

\int_{0}^{7} \frac{1}{( x - 3 ) ^{2}} d x

What is the integral from 1 to infinity of 3x^{-2} ?
The integral from 1 to infinity of 3x^{-2} is 3