What is the tangent of cos(x),\at x= pi/2 ?

The tangent of cos(x),\at x= pi/2 is y=-x+pi/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of cos(x),\at x= pi/2

tangent of

cos (x), at x = \frac{π}{2}

y = - x + \frac{π}{2}

Solution steps

Find the tangent point:

(\frac{π}{2}, 0)

Find the slope of

y = cos (x) : \frac{d y}{d x} = - sin (x)

Compute the slope of

y = cos (x)

x = \frac{π}{2} : m = - 1

Find the line with slope m=

- 1

and passing through

(\frac{π}{2}, 0) : y = - x + \frac{π}{2}

y = - x + \frac{π}{2}

\frac{d}{d r} (r 1 - r^{2})

x \to \infty lim (2 x - 1)

y^{^{'}} = y (1 - y), y (0) = - 2

\int \frac{y + 1}{y ^{2} + y + 1} d y

\frac{\partial}{\partial z} (x cos (y) sin (z))

What is the tangent of cos(x),\at x= pi/2 ?
The tangent of cos(x),\at x= pi/2 is y=-x+pi/2