What is the integral from 2 to 7 of 1/(sqrt(x+2)) ?

The integral from 2 to 7 of 1/(sqrt(x+2)) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 7 of 1/(sqrt(x+2))

\int_{2}^{7} \frac{1}{x + 2} d x

2

Solution steps

\int_{2}^{7} \frac{1}{x + 2} d x

Apply u-substitution

: \int_{2}^{3} 2 d u

= \int_{2}^{3} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{2}^{3}

Compute the boundaries:

2

= 2

\int_{0}^{1} p^{4} e^{- p} d p

\int_{1}^{2} \frac{y ^{3} + 4 y}{9 + y ^{4}} d y

\int_{1}^{\infty} e^{\frac{1}{x}} d x

\int_{2}^{4} 4 - x d x

\int_{0}^{2} \frac{x}{x ^{2} + 6 x + 8} d x

What is the integral from 2 to 7 of 1/(sqrt(x+2)) ?
The integral from 2 to 7 of 1/(sqrt(x+2)) is 2