What is the integral from-pi to pi of sin(2x)cos(2x) ?

The integral from-pi to pi of sin(2x)cos(2x) is 0

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integral from-pi to pi of sin(2x)cos(2x)

\int_{- π}^{π} sin (2 x) cos (2 x) d x

0

Solution steps

\int_{- π}^{π} sin (2 x) cos (2 x) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

sin (2 x) cos (2 x) :

Odd

= 0

\int_{x + 1}^{2 x} x d x

\int_{1}^{2} y cos (x y) d x

\int_{- 1}^{4} (4 + 3 x - x^{2}) d x

\int_{4}^{18} 16 + 3 x^{2} d x

\int_{0}^{\infty} m e^{- m x} d x

What is the integral from-pi to pi of sin(2x)cos(2x) ?
The integral from-pi to pi of sin(2x)cos(2x) is 0