What is the d/(dt)(-4sin(t)) ?

The d/(dt)(-4sin(t)) is -4cos(t)

What is the first d/(dt)(-4sin(t)) ?

The first d/(dt)(-4sin(t)) is -4cos(t)

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\frac{d}{d t} (- 4 sin (t))

- 4 cos (t)

Solution steps

\frac{d}{d t} (- 4 sin (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d t} (sin (t))

Apply the common derivative:

\frac{d}{d t} (sin (t)) = cos (t)

= - 4 cos (t)

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