What is the integral from x^2 to 8-x^2 of 1 ?

The integral from x^2 to 8-x^2 of 1 is 8-2x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from x^2 to 8-x^2 of 1

\int_{x^{2}}^{8 - x^{2}} 1 d y

8 - 2 x^{2}

Solution steps

\int_{x^{2}}^{8 - x^{2}} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{x^{2}}^{8 - x^{2}}

Simplify

= [y]_{x^{2}}^{8 - x^{2}}

Compute the boundaries:

8 - 2 x^{2}

= 8 - 2 x^{2}

\int_{0}^{54} x (\frac{1}{1458} x) d x

\int_{3}^{9} 7 arctan (x) d x

\int_{2}^{3} x^{3} - 8 d x

\int_{0}^{\infty} e^{- t} t^{7} d t

\int_{- 0.125}^{0.125} cos (x) d x

What is the integral from x^2 to 8-x^2 of 1 ?
The integral from x^2 to 8-x^2 of 1 is 8-2x^2