What is the integral from 0 to 2 of 4x^3-12x^2+8x ?

The integral from 0 to 2 of 4x^3-12x^2+8x is 0

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integral from 0 to 2 of 4x^3-12x^2+8x

\int_{0}^{2} 4 x^{3} - 12 x^{2} + 8 x d x

0

Solution steps

\int_{0}^{2} 4 x^{3} - 12 x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 4 x^{3} d x - \int_{0}^{2} 12 x^{2} d x + \int_{0}^{2} 8 x d x

\int_{0}^{2} 4 x^{3} d x = 16

\int_{0}^{2} 12 x^{2} d x = 32

\int_{0}^{2} 8 x d x = 16

= 16 - 32 + 16

Simplify

= 0

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What is the integral from 0 to 2 of 4x^3-12x^2+8x ?
The integral from 0 to 2 of 4x^3-12x^2+8x is 0