What is the integral from 0 to 4 of (x-4)^3 ?

The integral from 0 to 4 of (x-4)^3 is -64

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of (x-4)^3

\int_{0}^{4} (x - 4)^{3} d x

- 64

Solution steps

\int_{0}^{4} (x - 4)^{3} d x

Apply u-substitution

= \int_{- 4}^{0} u^{3} d u

Apply the Power Rule

= [\frac{u ^{4}}{4}]_{- 4}^{0}

Compute the boundaries:

- 64

= - 64

\int_{0}^{2} x^{2} - 6 x + 8 d x

\int_{0}^{3} (2 x + sin (2 π x)) d x

\int_{0}^{π} e^{x^{2}} sin (x) d x

\int_{0}^{2} e^{x + 1} d x

\int_{- 1.5}^{x} \frac{1}{4} d x

What is the integral from 0 to 4 of (x-4)^3 ?
The integral from 0 to 4 of (x-4)^3 is -64