What is the integral from-1 to 0 of (6x) ?

The integral from-1 to 0 of (6x) is -3

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integral from-1 to 0 of (6x)

\int_{- 1}^{0} (6 x) d x

- 3

Solution steps

\int_{- 1}^{0} 6 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{- 1}^{0} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 1}^{0}

= 6 [\frac{x ^{2}}{2}]_{- 1}^{0}

Compute the boundaries:

- \frac{1}{2}

= 6 (- \frac{1}{2})

Simplify

= - 3

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What is the integral from-1 to 0 of (6x) ?
The integral from-1 to 0 of (6x) is -3