What is the integral from 1 to 1 of 1/(4x^2-9) ?

The integral from 1 to 1 of 1/(4x^2-9) is 0

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integral from 1 to 1 of 1/(4x^2-9)

\int_{1}^{1} \frac{1}{4 x ^{2} - 9} d x

0

Solution steps

\int_{1}^{1} \frac{1}{4 x ^{2} - 9} d x

\int_{a}^{a} f (x) d x = 0, a \neq = \infty

= 0

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\int_{- 1}^{1} x^{3} + x d x

\int_{0}^{\infty} 3 e^{- \frac{x}{3}} d x

\int_{0}^{π} (2 cos (x)) d x

\int_{0}^{\frac{π}{2}} (e^{x} - sin (x)) d x

What is the integral from 1 to 1 of 1/(4x^2-9) ?
The integral from 1 to 1 of 1/(4x^2-9) is 0