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Popular >

integral from-2 to 1 of (2x^2+8)

Solution

\int_{- 2}^{1} (2 x^{2} + 8) d x

Solution

30

Solution steps

\int_{- 2}^{1} 2 x^{2} + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 2 x^{2} d x + \int_{- 2}^{1} 8 d x

\int_{- 2}^{1} 2 x^{2} d x = 6

\int_{- 2}^{1} 8 d x = 24

= 6 + 24

Simplify

= 30

Popular Examples

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\int_{- 1}^{1} (\frac{1}{3} + \frac{x ^{4}}{2}) d x

integral from-infinity to 0 of xe^{3x+1}

\int_{- \infty}^{0} x e^{3 x + 1} d x

integral from 0 to pi/8 of sin^3(8x)

\int_{0}^{\frac{π}{8}} sin^{3} (8 x) d x

integral from 1 to 3 of x^3-3x^2-x+3

\int_{1}^{3} x^{3} - 3 x^{2} - x + 3 d x

integral from 0 to 1 of tln(t^2+1)

\int_{0}^{1} t ln (t^{2} + 1) d t

Frequently Asked Questions (FAQ)

What is the integral from-2 to 1 of (2x^2+8) ?
The integral from-2 to 1 of (2x^2+8) is 30