What is the integral from-2 to 2 of x^2+ax^3+bx^4 ?

The integral from-2 to 2 of x^2+ax^3+bx^4 is (64b)/5+16/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 2 of x^2+ax^3+bx^4

\int_{- 2}^{2} x^{2} + a x^{3} + b x^{4} d x

\frac{64 b}{5} + \frac{16}{3}

Solution steps

\int_{- 2}^{2} x^{2} + a x^{3} + b x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} x^{2} d x + \int_{- 2}^{2} a x^{3} d x + \int_{- 2}^{2} b x^{4} d x

\int_{- 2}^{2} x^{2} d x = \frac{16}{3}

\int_{- 2}^{2} a x^{3} d x = 0

\int_{- 2}^{2} b x^{4} d x = \frac{64 b}{5}

= \frac{16}{3} + 0 + \frac{64 b}{5}

Simplify

= \frac{64 b}{5} + \frac{16}{3}

\int_{0.5}^{1} 1 d x

\int_{0}^{l n (2)} e^{2 x + 1} d x

\int_{6}^{5} x (x - 5)^{12} d x

\int_{1}^{x} (x^{2} y - y + 2) d y

\int_{0}^{4} 3 x^{3} - 3 x + 1 d x

What is the integral from-2 to 2 of x^2+ax^3+bx^4 ?
The integral from-2 to 2 of x^2+ax^3+bx^4 is (64b)/5+16/3