What is (d^2)/(dx^2)(sin(x)-cos(x)) ?

The answer to (d^2)/(dx^2)(sin(x)-cos(x)) is -sin(x)+cos(x)

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(d^2)/(dx^2)(sin(x)-cos(x))

\frac{d ^{2}}{d x ^{2}} (sin (x) - cos (x))

- sin (x) + cos (x)

Solution steps

\frac{d ^{2}}{d x ^{2}} (sin (x) - cos (x))

\frac{d}{d x} (sin (x) - cos (x)) = cos (x) + sin (x)

= \frac{d}{d x} (cos (x) + sin (x))

\frac{d}{d x} (cos (x) + sin (x)) = - sin (x) + cos (x)

= - sin (x) + cos (x)

6 (x^{2} + y^{2}) d x + 5 x y d y = 0

\frac{d}{d y} (\frac{y}{x + y + z})

7 x - 2 x

y = x^{2} + 9, (4, 25)

\frac{d}{d x} (arctan (x^{3} - x))

What is (d^2)/(dx^2)(sin(x)-cos(x)) ?
The answer to (d^2)/(dx^2)(sin(x)-cos(x)) is -sin(x)+cos(x)