What is the integral from 4 to infinity of e^{-y/2} ?

The integral from 4 to infinity of e^{-y/2} is 2/(e^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 4 to infinity of e^{-y/2}

\int_{4}^{\infty} e^{- \frac{y}{2}} d y

\frac{2}{e ^{2}}

Decimal Notation

0.27067 \dots

Solution steps

\int_{4}^{\infty} e^{- \frac{y}{2}} d y

Compute the indefinite integral:

\int e^{- \frac{y}{2}} d y = - 2 e^{- \frac{y}{2}} + C

Compute the boundaries:

\int_{4}^{\infty} e^{- \frac{y}{2}} d y = 0 - (- \frac{2}{e ^{2}})

= 0 - (- \frac{2}{e ^{2}})

Simplify

= \frac{2}{e ^{2}}

\int \frac{1}{3 - x ^{2}} d x

\int (sin (5 x) sin (x)) d x

1

\int \frac{x}{2 ( x + 1 ) 2 x + 1} d x

\frac{d}{d x} (\frac{x ^{3}}{3} - \frac{3}{x ^{5}} + 4 π)

What is the integral from 4 to infinity of e^{-y/2} ?
The integral from 4 to infinity of e^{-y/2} is 2/(e^2)