What is the integral from pi/2 to (-pi)/2 of ln(x) ?

The integral from pi/2 to (-pi)/2 of ln(x) is -integral from (-pi)/2 to pi/2 of ln(x)

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integral from pi/2 to (-pi)/2 of ln(x)

\int_{\frac{π}{2}}^{\frac{- π}{2}} ln (x) d x

- \int_{\frac{- π}{2}}^{\frac{π}{2}} ln (x) d x

Solution steps

\int_{\frac{π}{2}}^{\frac{- π}{2}} ln (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{\frac{- π}{2}}^{\frac{π}{2}} ln (x) d x

\int_{4}^{8} f (t) d t

\int_{- \frac{π}{2}}^{\frac{π}{2}} 4 cos (t) d t

\int_{0}^{1} e^{x} \cdot x d x

\int_{1}^{\infty} \frac{1}{2 x + 5} d x

\int_{0}^{\frac{π}{2}} tan^{5} (\frac{x}{2}) d x

What is the integral from pi/2 to (-pi)/2 of ln(x) ?
The integral from pi/2 to (-pi)/2 of ln(x) is -integral from (-pi)/2 to pi/2 of ln(x)