What is the integral from-2 to 1 of (2x^2-6x+5) ?

The integral from-2 to 1 of (2x^2-6x+5) is 30

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integral from-2 to 1 of (2x^2-6x+5)

\int_{- 2}^{1} (2 x^{2} - 6 x + 5) d x

30

Solution steps

\int_{- 2}^{1} 2 x^{2} - 6 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 2 x^{2} d x - \int_{- 2}^{1} 6 x d x + \int_{- 2}^{1} 5 d x

\int_{- 2}^{1} 2 x^{2} d x = 6

\int_{- 2}^{1} 6 x d x = - 9

\int_{- 2}^{1} 5 d x = 15

= 6 - (- 9) + 15

Simplify

= 30

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What is the integral from-2 to 1 of (2x^2-6x+5) ?
The integral from-2 to 1 of (2x^2-6x+5) is 30