What is the integral from-infinity to 0 of e^{17x} ?

The integral from-infinity to 0 of e^{17x} is 1/17

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integral from-infinity to 0 of e^{17x}

\int_{- \infty}^{0} e^{17 x} d x

\frac{1}{17}

Decimal Notation

0.05882 \dots

Solution steps

\int_{- \infty}^{0} e^{17 x} d x

Compute the indefinite integral:

\int e^{17 x} d x = \frac{1}{17} e^{17 x} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{17 x} d x = \frac{1}{17} - 0

= \frac{1}{17} - 0

Simplify

= \frac{1}{17}

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What is the integral from-infinity to 0 of e^{17x} ?
The integral from-infinity to 0 of e^{17x} is 1/17