What is the integral from 0 to 1 of (x+1)^5 ?

The integral from 0 to 1 of (x+1)^5 is 21/2

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integral from 0 to 1 of (x+1)^5

\int_{0}^{1} (x + 1)^{5} d x

\frac{21}{2}

Decimal Notation

10.5

Solution steps

\int_{0}^{1} (x + 1)^{5} d x

Apply u-substitution

: \int_{1}^{2} u^{5} d u

= \int_{1}^{2} u^{5} d u

Apply the Power Rule

: [\frac{u ^{6}}{6}]_{1}^{2}

= [\frac{u ^{6}}{6}]_{1}^{2}

Compute the boundaries:

\frac{21}{2}

= \frac{21}{2}

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What is the integral from 0 to 1 of (x+1)^5 ?
The integral from 0 to 1 of (x+1)^5 is 21/2