What is the integral from 1 to 4 of (sqrt(x))^2 ?

The integral from 1 to 4 of (sqrt(x))^2 is 15/2

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integral from 1 to 4 of (sqrt(x))^2

\int_{1}^{4} (x)^{2} d x

\frac{15}{2}

Decimal Notation

7.5

Solution steps

\int_{1}^{4} (x)^{2} d x

Simplify

(x)^{2} : x

= \int_{1}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{4}

= [\frac{x ^{2}}{2}]_{1}^{4}

Compute the boundaries:

\frac{15}{2}

= \frac{15}{2}

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What is the integral from 1 to 4 of (sqrt(x))^2 ?
The integral from 1 to 4 of (sqrt(x))^2 is 15/2