What is the integral from 1 to 2 of ln(3)-2sqrt(y) ?

The integral from 1 to 2 of ln(3)-2sqrt(y) is ln(3)-(2(4sqrt(2)-2))/3

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integral from 1 to 2 of ln(3)-2sqrt(y)

\int_{1}^{2} ln (3) - 2 y d y

ln (3) - \frac{2 ( 4 2 - 2 )}{3}

Decimal Notation

- 1.33929 \dots

Solution steps

\int_{1}^{2} ln (3) - 2 y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} ln (3) d y - \int_{1}^{2} 2 y d y

\int_{1}^{2} ln (3) d y = ln (3)

\int_{1}^{2} 2 y d y = \frac{2 ( 4 2 - 2 )}{3}

= ln (3) - \frac{2 ( 4 2 - 2 )}{3}

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What is the integral from 1 to 2 of ln(3)-2sqrt(y) ?
The integral from 1 to 2 of ln(3)-2sqrt(y) is ln(3)-(2(4sqrt(2)-2))/3