What is the integral from 0 to pi of 8cos(x) ?

The integral from 0 to pi of 8cos(x) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi of 8cos(x)

\int_{0}^{π} 8 cos (x) d x

0

Solution steps

\int_{0}^{π} 8 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 8 [sin (x)]_{0}^{π}

Compute the boundaries:

0

= 8 \cdot 0

Simplify

= 0

\int_{0}^{1} π (1 - y) d y

\int_{4}^{9} x^{3} d x

\int_{1}^{2} x^{2} - 3 d x

\int_{2}^{5} 2 x - 3 d x

\int_{0}^{10} 8000 e^{- 0.005 t} d t

What is the integral from 0 to pi of 8cos(x) ?
The integral from 0 to pi of 8cos(x) is 0