What is the integral from 2 to 3 of (2+2y)^2 ?

The integral from 2 to 3 of (2+2y)^2 is 148/3

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integral from 2 to 3 of (2+2y)^2

\int_{2}^{3} (2 + 2 y)^{2} d y

\frac{148}{3}

Decimal Notation

49.33333 \dots

Solution steps

\int_{2}^{3} (2 + 2 y)^{2} d y

Apply u-substitution

: \int_{6}^{8} \frac{u ^{2}}{2} d u

= \int_{6}^{8} \frac{u ^{2}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{6}^{8} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{6}^{8}

= \frac{1}{2} [\frac{u ^{3}}{3}]_{6}^{8}

Compute the boundaries:

\frac{296}{3}

= \frac{1}{2} \cdot \frac{296}{3}

Simplify

= \frac{148}{3}

\int_{0}^{1} - 1 + \frac{π x}{2} d x

\int_{1}^{2} x (x - 1) d x

\int_{3}^{4} - x ln (x - 3) d x

\int_{0}^{\frac{π}{2}} 1 - sin^{2} (x) d x

\int_{0}^{2} 3 x d x

What is the integral from 2 to 3 of (2+2y)^2 ?
The integral from 2 to 3 of (2+2y)^2 is 148/3