What is the integral from 0 to 1 of 11ln(x) ?

The integral from 0 to 1 of 11ln(x) is -11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 11ln(x)

\int_{0}^{1} 11 ln (x) d x

- 11

Solution steps

\int_{0}^{1} 11 ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 11 \cdot \int_{0}^{1} ln (x) d x

Apply Integration By Parts

: [x ln (x) - \int 1 d x]_{0}^{1}

= 11 [x ln (x) - \int 1 d x]_{0}^{1}

\int 1 d x = x

= 11 [x ln (x) - x]_{0}^{1}

Compute the boundaries:

- 1

= 11 (- 1)

Simplify

= - 11

\int_{0}^{t} 120 e^{- 10 t} d t

\int_{e}^{e^{2}} x^{2} ln (x) d x

\int_{0}^{1} \frac{( y ^{2} + y ^{3} )}{2} d y

\int_{0}^{\frac{3}{2}} 3 - x^{2} d x

\int_{0}^{1 - x} x^{2} + y^{2} d y

What is the integral from 0 to 1 of 11ln(x) ?
The integral from 0 to 1 of 11ln(x) is -11