What is the integral from 1 to 2 of 1/(sqrt(t-1)) ?

The integral from 1 to 2 of 1/(sqrt(t-1)) is 2

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integral from 1 to 2 of 1/(sqrt(t-1))

\int_{1}^{2} \frac{1}{t - 1} d t

2

Solution steps

\int_{1}^{2} \frac{1}{t - 1} d t

Apply u-substitution

: \int_{0}^{1} 2 d u

= \int_{0}^{1} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{1}

Compute the boundaries:

2

= 2

\int_{0}^{1} 2 e^{- 2 t} d t

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\int_{0}^{1} ln (3 x + 1) d x

\int_{x}^{x} e^{\frac{x}{y}} d y

What is the integral from 1 to 2 of 1/(sqrt(t-1)) ?
The integral from 1 to 2 of 1/(sqrt(t-1)) is 2