What is the solution for (dx)/(dt)=x^2+1/36 ?

The solution for (dx)/(dt)=x^2+1/36 is x=(tan((t+c_{1})/6))/(6)

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(dx)/(dt)=x^2+1/36

\frac{d x}{d t} = x^{2} + \frac{1}{36}

x = \frac{tan ( \frac{t + c _{1}}{6} )}{6}

Solution steps

\frac{d x}{d t} = x^{2} + \frac{1}{36}

Solve separable ODE:

x = \frac{tan ( \frac{t + c _{1}}{6} )}{6}

x = \frac{tan ( \frac{t + c _{1}}{6} )}{6}

\frac{d}{d x} (x^{2} - x + 1)

y = x (2 x + 3)

\frac{d}{d x} (x (x + 1))

\frac{d}{d x} (ln (2 x y + 4))

\int e^{\frac{1}{2} x} d x

What is the solution for (dx)/(dt)=x^2+1/36 ?
The solution for (dx)/(dt)=x^2+1/36 is x=(tan((t+c_{1})/6))/(6)