What is the integral from 1 to 5 of x^2-4x-12 ?

The integral from 1 to 5 of x^2-4x-12 is -164/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 5 of x^2-4x-12

\int_{1}^{5} x^{2} - 4 x - 12 d x

- \frac{164}{3}

Decimal Notation

- 54.66666 \dots

Solution steps

\int_{1}^{5} x^{2} - 4 x - 12 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} x^{2} d x - \int_{1}^{5} 4 x d x - \int_{1}^{5} 12 d x

\int_{1}^{5} x^{2} d x = \frac{124}{3}

\int_{1}^{5} 4 x d x = 48

\int_{1}^{5} 12 d x = 48

= \frac{124}{3} - 48 - 48

Simplify

\frac{124}{3} - 48 - 48 : - \frac{164}{3}

= - \frac{164}{3}

\int_{0}^{2} \frac{1}{t - 2} d t

\int_{2}^{8} x^{2} + x + 1 + \frac{1}{x} d x

\int_{0}^{5} (- 3 x - 5 x^{2}) d x

\int_{3}^{7} e^{x} - 3 x d x

\int_{1}^{4} \frac{1}{x - 3} d x

What is the integral from 1 to 5 of x^2-4x-12 ?
The integral from 1 to 5 of x^2-4x-12 is -164/3