What is the integral from 2 to infinity of e^{5-6x} ?

The integral from 2 to infinity of e^{5-6x} is 1/(6e^7)

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integral from 2 to infinity of e^{5-6x}

\int_{2}^{\infty} e^{5 - 6 x} d x

\frac{1}{6 e ^{7}}

Decimal Notation

0.00015 \dots

Solution steps

\int_{2}^{\infty} e^{5 - 6 x} d x

Compute the indefinite integral:

\int e^{5 - 6 x} d x = - \frac{1}{6} e^{5 - 6 x} + C

Compute the boundaries:

\int_{2}^{\infty} e^{5 - 6 x} d x = 0 - (- \frac{1}{6 e ^{7}})

= 0 - (- \frac{1}{6 e ^{7}})

Simplify

= \frac{1}{6 e ^{7}}

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What is the integral from 2 to infinity of e^{5-6x} ?
The integral from 2 to infinity of e^{5-6x} is 1/(6e^7)