What is the integral from-1 to 9 of 0.048x^3-2x ?

The integral from-1 to 9 of 0.048x^3-2x is -1.28

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integral from-1 to 9 of 0.048x^3-2x

\int_{- 1}^{9} 0.048 x^{3} - 2 x d x

- 1.28

Solution steps

\int_{- 1}^{9} 0.048 x^{3} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{9} 0.048 x^{3} d x - \int_{- 1}^{9} 2 x d x

\int_{- 1}^{9} 0.048 x^{3} d x = 78.72

\int_{- 1}^{9} 2 x d x = 80

= 78.72 - 80

Simplify

= - 1.28

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What is the integral from-1 to 9 of 0.048x^3-2x ?
The integral from-1 to 9 of 0.048x^3-2x is -1.28