What is the integral from 0 to 1 of x/(sqrt(4-x^4)) ?

The integral from 0 to 1 of x/(sqrt(4-x^4)) is pi/(12)

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integral from 0 to 1 of x/(sqrt(4-x^4))

\int_{0}^{1} \frac{x}{4 - x ^{4}} d x

\frac{π}{12}

Decimal Notation

0.26179 \dots

Solution steps

\int_{0}^{1} \frac{x}{4 - x ^{4}} d x

Compute the indefinite integral:

\int \frac{x}{4 - x ^{4}} d x = \frac{1}{2} arcsin (\frac{1}{2} x^{2}) + C

Compute the boundaries:

\int_{0}^{1} \frac{x}{4 - x ^{4}} d x = \frac{π}{12} - 0

= \frac{π}{12} - 0

Simplify

= \frac{π}{12}

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What is the integral from 0 to 1 of x/(sqrt(4-x^4)) ?
The integral from 0 to 1 of x/(sqrt(4-x^4)) is pi/(12)