What is the integral from 1 to 4 of-3x ?

The integral from 1 to 4 of-3x is -45/2

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integral from 1 to 4 of-3x

\int_{1}^{4} - 3 x d x

- \frac{45}{2}

Decimal Notation

- 22.5

Solution steps

\int_{1}^{4} - 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int_{1}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{4}

= - 3 [\frac{x ^{2}}{2}]_{1}^{4}

Compute the boundaries:

\frac{15}{2}

= - 3 \cdot \frac{15}{2}

Simplify

= - \frac{45}{2}

\int_{1}^{2} \frac{5}{t ^{6}} d t

\int_{1}^{\infty} (\frac{1}{2})^{x} d x

\int_{1}^{3} (x - 1) (3 - x) d x

\int_{0}^{1} 1 - r^{2} d r

\int_{0}^{2} \frac{ln ( x )}{x ^{2}} d x

What is the integral from 1 to 4 of-3x ?
The integral from 1 to 4 of-3x is -45/2