What is the solution for derivative of f(x)=(e^x)/(x^2-1) ?

The solution for derivative of f(x)=(e^x)/(x^2-1) is f(x)=integral of (e^x)/(x^2-1)

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derivative of f(x)=(e^x)/(x^2-1)

\frac{d}{d x} f (x) = \frac{e ^{x}}{x ^{2} - 1}

f (x) = \int \frac{e ^{x}}{x ^{2} - 1} d x

Solution steps

\frac{df}{d x} = \frac{e ^{x}}{x ^{2} - 1}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{e ^{x}}{x ^{2} - 1} d x

f (x) = \int \frac{e ^{x}}{x ^{2} - 1} d x

f^{^{'}} (x) = x - 1

\frac{\partial}{\partial x} (2 x y + 1)

y^{^{''}} - 5 y^{^{'}} = 2 t

f (x) = 2 x^{2} + x - 1

n = 4 \sum \infty n! (x - 4)^{n}

What is the solution for derivative of f(x)=(e^x)/(x^2-1) ?
The solution for derivative of f(x)=(e^x)/(x^2-1) is f(x)=integral of (e^x)/(x^2-1)