What is the integral from 2 to 5 of 1/((x-2)^0) ?

The integral from 2 to 5 of 1/((x-2)^0) is 3

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integral from 2 to 5 of 1/((x-2)^0)

\int_{2}^{5} \frac{1}{( x - 2 ) ^{0}} d x

3

Solution steps

\int_{2}^{5} \frac{1}{( x - 2 ) ^{0}} d x

Simplify

= \int_{2}^{5} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{2}^{5}

Simplify

= [x]_{2}^{5}

Compute the boundaries:

3

= 3

\int_{0}^{l n (10)} x e^{x} d x

\int_{0}^{\frac{π}{2}} x - cos (y) d y

\int_{0}^{6} 3 + 2 cos (\frac{π x}{6}) d x

\int_{0}^{2} e^{x^{4}} x^{3} d x

What is the integral from 2 to 5 of 1/((x-2)^0) ?
The integral from 2 to 5 of 1/((x-2)^0) is 3