What is the integral from 0 to 1.5 of (2x-3) ?

The integral from 0 to 1.5 of (2x-3) is -2.25

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integral from 0 to 1.5 of (2x-3)

\int_{0}^{1.5} (2 x - 3) d x

- 2.25

Solution steps

\int_{0}^{1.5} 2 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1.5} 2 x d x - \int_{0}^{1.5} 3 d x

\int_{0}^{1.5} 2 x d x = 2.25

\int_{0}^{1.5} 3 d x = 4.5

= 2.25 - 4.5

Simplify

= - 2.25

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\int_{0}^{2} (\frac{1}{x ^{2} + x + 1}) d x

What is the integral from 0 to 1.5 of (2x-3) ?
The integral from 0 to 1.5 of (2x-3) is -2.25