What is the integral from-2x to 3x^2 of cos(t) ?

The integral from-2x to 3x^2 of cos(t) is sin(3x^2)+sin(2x)

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integral from-2x to 3x^2 of cos(t)

\int_{- 2 x}^{3 x^{2}} cos (t) d t

sin (3 x^{2}) + sin (2 x)

Solution steps

\int_{- 2 x}^{3 x^{2}} cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= [sin (t)]_{- 2 x}^{3 x^{2}}

Compute the boundaries:

sin (3 x^{2}) + sin (2 x)

= sin (3 x^{2}) + sin (2 x)

\int_{0}^{1} ln x^{2} + 1 d x

\int_{1}^{z} y e^{y^{2} - z} d y

\int_{0}^{1} (3 x^{2} + 2 x) d x

\int_{0}^{10} sin (\frac{π x}{10}) d x

\int_{- \infty}^{0} z e^{6 z} d z

What is the integral from-2x to 3x^2 of cos(t) ?
The integral from-2x to 3x^2 of cos(t) is sin(3x^2)+sin(2x)