What is the integral from 5 to infinity of e^{-4x} ?

The integral from 5 to infinity of e^{-4x} is 1/(4e^{20)}

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integral from 5 to infinity of e^{-4x}

\int_{5}^{\infty} e^{- 4 x} d x

\frac{1}{4 e ^{20}}

Decimal Notation

5.15288 E - 10

Solution steps

\int_{5}^{\infty} e^{- 4 x} d x

Compute the indefinite integral:

\int e^{- 4 x} d x = - \frac{1}{4} e^{- 4 x} + C

Compute the boundaries:

\int_{5}^{\infty} e^{- 4 x} d x = 0 - (- \frac{1}{4 e ^{20}})

= 0 - (- \frac{1}{4 e ^{20}})

Simplify

= \frac{1}{4 e ^{20}}

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What is the integral from 5 to infinity of e^{-4x} ?
The integral from 5 to infinity of e^{-4x} is 1/(4e^{20)}