What is the integral from-1 to 1 of (x^2-2-x^2) ?

The integral from-1 to 1 of (x^2-2-x^2) is -4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of (x^2-2-x^2)

\int_{- 1}^{1} (x^{2} - 2 - x^{2}) d x

- 4

Solution steps

\int_{- 1}^{1} x^{2} - 2 - x^{2} d x

Simplify

= \int_{- 1}^{1} - 2 d x

Integral of a constant:

\int a d x = a x

= [(- 2) x]_{- 1}^{1}

Simplify

= [- 2 x]_{- 1}^{1}

Compute the boundaries:

- 4

= - 4

\int_{0}^{1} (x^{4})^{2} - (x^{7})^{2} d x

\int_{- 2}^{1} (2 x + 3)^{2} d x

\int_{2}^{1} (ln (4 x))^{2} d x

\int_{0}^{π} 5 sin (t) d t

\int_{l n (4)}^{l n (5)} e^{x} d x

What is the integral from-1 to 1 of (x^2-2-x^2) ?
The integral from-1 to 1 of (x^2-2-x^2) is -4