What is the integral from-3 to 4 of |+1| ?

The integral from-3 to 4 of |+1| is 7

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integral from-3 to 4 of |+1|

\int_{- 3}^{4} ∣ + 1 ∣ d x

7

Solution steps

\int_{- 3}^{4} ∣ 1 ∣ d x

Integral of a constant:

\int a d x = a x

= [∣ 1 ∣ x]_{- 3}^{4}

Simplify

∣ 1 ∣ x : x

= [x]_{- 3}^{4}

Compute the boundaries:

7

= 7

\int_{0}^{2} 3 x^{2} - 1 d x

\int_{0}^{20} (2 x - 20) d x

\int_{0}^{2 π} 8 t 2 d t

\int_{- 1}^{1} (2 - x^{2})^{\frac{3}{2}} d x

\int_{0}^{r} (a r^{3} + b r) 2 π r d r

What is the integral from-3 to 4 of |+1| ?
The integral from-3 to 4 of |+1| is 7