What is the integral from 0 to 4 of 4sqrt(2)t ?

The integral from 0 to 4 of 4sqrt(2)t is 32sqrt(2)

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integral from 0 to 4 of 4sqrt(2)t

\int_{0}^{4} 42 t d t

322

Decimal Notation

45.25483 \dots

Solution steps

\int_{0}^{4} 42 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 42 \cdot \int_{0}^{4} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{0}^{4}

= 42 [\frac{t ^{2}}{2}]_{0}^{4}

Compute the boundaries:

8

= 42 \cdot 8

Simplify

= 322

\int_{0}^{2} \frac{2 x}{x + 1} d x

\int_{0}^{π} \frac{1}{2 x + π} d x

\int_{1}^{y} (2 x y + y^{2}) d x

\int_{- 1}^{2} x^{3} + 8 d x

\int_{- π}^{π} ∣ t ∣ d t

What is the integral from 0 to 4 of 4sqrt(2)t ?
The integral from 0 to 4 of 4sqrt(2)t is 32sqrt(2)