en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of (2x-3)

Solution

\int_{0}^{4} (2 x - 3) d x

Solution

4

Solution steps

\int_{0}^{4} 2 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 x d x - \int_{0}^{4} 3 d x

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 3 d x = 12

= 16 - 12

Simplify

= 4

Popular Examples

integral from 0 to 1 of pi(y-y^2)^2

\int_{0}^{1} π (y - y^{2})^{2} d y

integral from 2 to \sqrt[3]{3 of} 1/x

integral from x to 2 of t

\int_{x}^{2} t d t

integral from 0 to x/2 of sqrt(sin(x))

\int_{0}^{\frac{x}{2}} sin (x) d x

integral from 1 to infinity of 8/(x^5)

\int_{1}^{\infty} \frac{8}{x ^{5}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (2x-3) ?
The integral from 0 to 4 of (2x-3) is 4