What is the integral of 16ln(\sqrt[3]{x}) ?

The integral of 16ln(\sqrt[3]{x}) is 16(1/3 xln(x)-1/3 x)+C

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integral of 16ln(\sqrt[3]{x})

16 (\frac{1}{3} x ln (x) - \frac{1}{3} x) + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply Integration By Parts

\int \frac{1}{3} d x = \frac{1}{3} x

Simplify

= 16 (\frac{1}{3} x ln (x) - \frac{1}{3} x)

Add a constant to the solution

= 16 (\frac{1}{3} x ln (x) - \frac{1}{3} x) + C

\frac{d y}{d x} + 2 y = k

f (x) = e^{x^{2}}, at x = \frac{1}{2}

\int \frac{1}{p} d p

\int \frac{4 x ^{2} - x + 25}{x ^{3} + 25 x} d x

1 + \frac{1}{x}

What is the integral of 16ln(\sqrt[3]{x}) ?
The integral of 16ln(\sqrt[3]{x}) is 16(1/3 xln(x)-1/3 x)+C