What is the integral from pi/4 to pi/2 of sin^3(x) ?

The integral from pi/4 to pi/2 of sin^3(x) is 5/(6sqrt(2))

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integral from pi/4 to pi/2 of sin^3(x)

\int_{\frac{π}{4}}^{\frac{π}{2}} sin^{3} (x) d x

\frac{5}{6 2}

Decimal Notation

0.58925 \dots

Solution steps

\int_{\frac{π}{4}}^{\frac{π}{2}} sin^{3} (x) d x

Rewrite using trig identities

= \int_{\frac{π}{4}}^{\frac{π}{2}} (1 - cos^{2} (x)) sin (x) d x

Apply u-substitution

: \int_{\frac{2}{2}}^{0} - 1 + u^{2} d u

= \int_{\frac{2}{2}}^{0} - 1 + u^{2} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{\frac{2}{2}} - 1 + u^{2} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (- \int_{0}^{\frac{2}{2}} 1 d u + \int_{0}^{\frac{2}{2}} u^{2} d u)

\int_{0}^{\frac{2}{2}} 1 d u = \frac{1}{2}

\int_{0}^{\frac{2}{2}} u^{2} d u = \frac{1}{6 2}

= - (- \frac{1}{2} + \frac{1}{6 2})

Simplify

- (- \frac{1}{2} + \frac{1}{6 2}) : \frac{5}{6 2}

= \frac{5}{6 2}

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What is the integral from pi/4 to pi/2 of sin^3(x) ?
The integral from pi/4 to pi/2 of sin^3(x) is 5/(6sqrt(2))