What is the integral from 0 to 12 of 9800*9pi*(12-x) ?

The integral from 0 to 12 of 9800*9pi*(12-x) is 6350400pi

Popular >

integral from 0 to 12 of 98009pi(12-x)

\int_{0}^{12} 9800 \cdot 9 π \cdot (12 - x) d x

6350400 π

Decimal

19950369.98735 \dots

Solution steps

\int_{0}^{12} 9800 \cdot 9 π (12 - x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9800 \cdot 9 π \cdot \int_{0}^{12} 12 - x d x

Simplify

= 88200 π \cdot \int_{0}^{12} 12 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 88200 π (\int_{0}^{12} 12 d x - \int_{0}^{12} x d x)

\int_{0}^{12} 12 d x = 144

\int_{0}^{12} x d x = 72

= 88200 π (144 - 72)

Simplify

= 6350400 π

\int_{- 1}^{2} (x + x^{4}) d x

\int_{0}^{2} 0.5 e^{- 0.5 x} d x

\int_{0}^{1} (x^{3} + 3 x^{2}) d x

\int_{0}^{3} \frac{3 x ( 8 - x )}{256} d x

\int_{1}^{\infty} \frac{1}{2 x + 3} d x

What is the integral from 0 to 12 of 9800*9pi*(12-x) ?
The integral from 0 to 12 of 9800*9pi*(12-x) is 6350400pi